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In the following system of linear equations 7x−15y=27x - 15y = 2 and x+2y=3x + 2y = 3, the value of x and y is:

Solution

✅ Correct Option: 1

From the second equation, x=3−2yx = 3 - 2y.

Substituting: 7(3−2y)−15y=2⇒21−29y=2⇒y=19/297(3-2y) - 15y = 2 \Rightarrow 21 - 29y = 2 \Rightarrow y = 19/29.

Then x=3−38/29=49/29x = 3 - 38/29 = 49/29.

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