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A can do a certain work in 12 days. B is 60% more efficient than A. How many days does B alone take to do the same work ?

Solution

✅ Correct Option: 1

Efficiency and time are inversely proportional.

If A's efficiency is 100100, B's is 160160, so the ratio of efficiencies is 5:85 : 8 and the ratio of times is 8:58 : 5.

Time for B =12×58=7.5= 12 \times \dfrac{5}{8} = 7.5 days.

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