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A boy is running at a speed of p km/hr to cover a distance of 1 km. But, due to the slippery ground, his speed is reduced by q km/hr (p>q). If he takes r hours to cover the distance, then

Solution

✅ Correct Option: 1

A boy wants to run 1 km at a speed of pp km/hr. Due to slippery ground, his speed is reduced by qq km/hr. He takes rr hours to complete the distance.

The actual speed of the boy is:

Actual speed =p−q= p - q km/hr


Using the distance-speed-time relationship:

Distance == Speed ×\times Time

Substituting the given values:

1=(p−q)×r1 = (p - q) \times r


Rearranging the equation:

1=r(p−q)1 = r(p - q)

Dividing both sides by rr:

1r=p−q\dfrac{1}{r} = p - q

Therefore, the relationship between pp, qq, and rr is 1r=p−q\dfrac{1}{r} = p - q.

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