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Match List-I with List-II

List-IList-II
(A) Raoult's law(I) p=kB.xp = k_B.x
(B) Henry's law(II) ΔTf=Kfm\Delta T_f = K_f m
(C) Elevation of boiling point(III) p=x1p1°+x2p2°p = x_1p_1^° + x_2p_2^°
(D) Depression in freezing point(IV) ΔTb=Kbm\Delta T_b = K_b m

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Option 1: (A)-(I), (B)-(II), (C)-(III), (D)-(IV) -> Incorrectly matches Raoult's law with Henry's law equation and misplaces colligative property formulas.

Option 2: (A)-(III), (B)-(I), (C)-(IV), (D)-(II) -> Correctly matches all laws and colligative properties with their respective equations.

Option 3: (A)-(II), (B)-(III), (C)-(I), (D)-(IV) -> Incorrectly assigns freezing point depression formula to Raoult's law and completely mismatches others.

Option 4: (A)-(III), (B)-(IV), (C)-(I), (D)-(II) -> While Raoult's law is correct, Henry's law is wrongly matched with boiling point elevation.


Hence, Option 2: (A)-(III), (B)-(I), (C)-(IV), (D)-(II) -> Raoult's law (p=x1p1°+x2p2°p = x_1p_1^° + x_2p_2^°) gives total vapor pressure in ideal solutions, Henry's law (p=kB.xp = k_B.x) relates gas solubility to partial pressure, elevation of boiling point uses ΔTb=Kbm\Delta T_b = K_b m, and depression in freezing point uses ΔTf=Kfm\Delta T_f = K_f m -> correct

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