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Alisha goes 30 meters North, then turns right and walks 40 meters, then she again turns right and walks 20 meters, then again she turns right and walks 40 meters. How many meters is Alisha finally from her original position?

Solution

✅ Correct Option: 2

Let the starting position be at the origin with coordinates (0,0)(0, 0).

Alisha goes 30 meters North:

Position: (0,30)(0, 30)


Turns right (now facing East) and walks 40 meters:

Position: (40,30)(40, 30)


Turns right again (now facing South) and walks 20 meters:

Position: (40,10)(40, 10)


Turns right again (now facing West) and walks 40 meters:

Position: (0,10)(0, 10)


The distance from the original position (0,0)(0, 0) to the final position (0,10)(0, 10) is:

d=(0−0)2+(10−0)2d = \sqrt{(0-0)^2 + (10-0)^2}

d=0+100d = \sqrt{0 + 100}

d=100d = \sqrt{100}

d=10d = 10

Therefore, Alisha is 10 meters from her original position.

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