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A certain amount, when put at a compound rate of interest, becomes double in 5 years. In how many years will the amount become eight times?

Solution

✅ Correct Option: 4

When an amount is placed at compound interest and becomes double in 5 years, the time required for it to become eight times can be found using the doubling pattern.


In compound interest, the amount grows by multiplication. Since the amount doubles in 5 years:

After 5 years: Amount =2×= 2 \times original

After 10 years: Amount =2×2=4×= 2 \times 2 = 4 \times original

After 15 years: Amount =4×2=8×= 4 \times 2 = 8 \times original


Using the compound interest formula A=P(1+r)tA = P(1 + r)^t

Since the amount doubles in 5 years:

2=(1+r)52 = (1 + r)^5

For the amount to become 8 times:

8=(1+r)t8 = (1 + r)^t


Since 8=238 = 2^3:

8=238 = 2^3

8=[(1+r)5]38 = [(1 + r)^5]^3

8=(1+r)158 = (1 + r)^{15}

Therefore t=15t = 15 years


The amount will become eight times in 15 years.

When money doubles in nn years, it becomes 2k2^k times in k×nk \times n years. Here, 8=238 = 2^3 and n=5n = 5, so the time required is 3×5=153 \times 5 = 15 years.

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