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Solution

✅ Correct Option: 3

To identify the odd one out, we need to examine the properties of each number.

Checking if each number is prime:

For 191:

Testing divisibility by primes up to 191≈13.8\sqrt{191} \approx 13.8

191 is not divisible by 2, 3, 5, 7, 11, or 13

Therefore, 191 is prime.


For 149:

Testing divisibility by primes up to 149≈12.2\sqrt{149} \approx 12.2

149 is not divisible by 2, 3, 5, 7, or 11

Therefore, 149 is prime.


For 273:

Testing divisibility: 273÷3=91273 \div 3 = 91

273=3×91273 = 3 \times 91

273=3×7×13273 = 3 \times 7 \times 13

Therefore, 273 is composite (not prime).


For 233:

Testing divisibility by primes up to 233≈15.3\sqrt{233} \approx 15.3

233 is not divisible by 2, 3, 5, 7, 11, or 13

Therefore, 233 is prime.


The numbers 191, 149, and 233 are all prime numbers.

The number 273 is a composite number.

Therefore, 273 is the odd one out.

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