Quantitative Reasoning

Probability

Easy

If A and B are two disjoint events then

A. A ∩ B = Φ

B. P ( A ∩ B ) = 0

C. P ( A ∪ B ) = P (A) + P (B)

D. P ( A ∩ B ) = 1

Choose the correct answer from the options given below:

A, C, D only

A, B, D only

A, B, C Only

B, C, D only

✅ Correct Option: 3

Disjoint (mutually exclusive) events cannot occur together, so $A \cap B = \Phi$ and hence $P(A \cap B) = 0$ . The addition rule $P(A \cup B) = P(A) + P(B) - P(A \cap B)$ reduces to $P(A) + P(B)$ . Statement D claims $P(A \cap B) = 1$ , which contradicts B. So A, B and C are correct.

2026: 25 May Shift 2

Three unbiased coins are tossed. What is the probability of getting at least 2 heads?

2026: 12 May Shift 1

If A and B are mutually exclusive events, then following probability of the events are given below:

(A) P(A) =0.4, P(B) =0.4 and P(AUB)=0.8

(B) P(A) =0.3, P(B) =0.6 and P(AUB)=0.9

(D) P(A) =0.1, P(B) =0.1 and P(AUB)=0.2

which of the following options is correct?

2025: 16 May Shift 1

If three unbiased coins are tossed simultaneously, then the probability of exactly two heads is:

2025: 15 May Shift 1

One card is drawn from a well-shuffled deck of 52 cards. Find the probability that the card be an ace.

2025: 3 June Shift 1

Three unbiased coins are tossed. What is the probability of getting at least 2 heads?

2023: 19 June Shift 1

'A' spins a spinner that is split into 10 equal sections marked as 1, 3, 2, 1, 2, 2, 3, 1, 2, 1. What is the probability that the spinner will land on number 2 ?

If A and B are two disjoint events then A. A ∩ B = Φ B. P ( A ∩ B ) = 0 C. P ( A ∪ B ) = P (A) + P (B) D. P ( A ∩ B ) = 1 Choose the correct answer from the options given below:

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

If A and B are two disjoint events then

A. A ∩ B = Φ

B. P ( A ∩ B ) = 0

C. P ( A ∪ B ) = P (A) + P (B)

D. P ( A ∩ B ) = 1

Choose the correct answer from the options given below: