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If point P(4, 2) lies on the circle having centre O(-1, 1), and C is the circumference of the circle, then value of 49C249C^2, is:

Solution

✅ Correct Option: 1

Radius =(4+1)2+(2−1)2=26= \sqrt{(4+1)^2 + (2-1)^2} = \sqrt{26}.

Circumference C=2πrC = 2\pi r, so C2=4π2×26C^2 = 4\pi^2 \times 26.

Taking π=22/7\pi = 22/7, C2=4×484×2649=5033649C^2 = \frac{4 \times 484 \times 26}{49} = \frac{50336}{49}.

Hence 49C2=5033649C^2 = 50336.

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