Find the maximum distance between two points on the perimeter of a rectangular garden whose length and breadth are 20 meter and 15 meter.

If the side of a square is increased by 8 cm, its area increases by 120 sq. cm. Find the side of the square.

If lengths of two diagonals of rectangle are $(2x - 3)$ cm and $(x + 2)$ cm, then the value of x is:

The distance between two parallel sides of a trapezium is 15 m and its area is 480 m$^2$. If one of the parallel sides is 20 m long, then length of the other side is:

The length of one pair of opposite sides of a square is increased by 4 cm on each side; the ratio of the length and the breadth of the newly formed rectangle becomes 5 : 3. Find the area of the original square?

If the points P(8,5), Q(4,8), R(0,5) and S(4,k) are the vertices of a rhombus, taken in order, then the value of k is

Consider the area of the following solids:

(A) A rhombus whose diagonals are 48 cm and 20 cm long.

(B) A trapezium with parallel sides 9.7 cm and 6.3 cm, and the distance between them is 6.5 cm.

(C) A parallelogram with a base equal to 25 cm and the corresponding height measuring 16.8 cm.

(D) A rhombus, whose diagonals are 30 cm and 16 cm.

Arrange the above in ascending order.

Choose the correct answer from the options given below: