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Solution

Correct Option: 1

Note that 25+(29)+4=025 + (-29) + 4 = 0.

When a+b+c=0a + b + c = 0, we have a3+b3+c3=3abca^3 + b^3 + c^3 = 3abc.

So (25)3+(29)3+(4)3=3×25×(29)×4=8700(25)^3 + (-29)^3 + (4)^3 = 3 \times 25 \times (-29) \times 4 = -8700.

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