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Sunit is going towards north, after going 8 km he turns left and goes 6 km. What is the distance of Sunit from initial point.

Solution

Correct Option: 2

Sunit goes 8 km north, then turns left (west) and goes 6 km. The path forms a right angle.

By the Pythagorean theorem, distance from starting point =82+62=64+36=100=10= \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10 km.

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