Skip to main contentSkip to solution
Figure for CUET General Test 2022 6 Oct Shift 1 question 64 (Geometry)

Study the adjoining picture and answer the following questions:

Area of triangle AFC is.

Solution

Correct Option: 3

Triangle AFCAFC has vertex AA at the top and base FCFC.

Area =12×base×height= \dfrac{1}{2} \times \text{base} \times \text{height}


From the figure, using base FCFC and the perpendicular height from AA:

Area =12×10×25= \dfrac{1}{2} \times 10 \times 25

=125 m2= 125 \text{ m}^2


The area of triangle AFCAFC is 125 m2125 \text{ m}^2.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question