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The angle of depression of a point situated at a distance 500 m from the base of tower is 45°45°. The height of tower is _____.

Solution

Correct Option: 4

If angle of depression is 45°45° from the top of tower to a point 500 m from base, then tan45°=height500=1\tan 45° = \frac{\text{height}}{500} = 1. So height =500= 500 m.

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