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From a point P on the ground the angle of elevation of the top of 10 m high building is 30°30°. A flag is hoisted at the top of the building and the angle of elevation of the top of the flagstaff from the point P is 45°45°. Length of the flagstaff is:

(Take 3=1.732\sqrt{3} = 1.732)

Solution

Correct Option: 4

Let horizontal distance from P to building be dd. From tan30°=10/d\tan 30° = 10/d: d=103d = 10\sqrt{3}.

Let flagstaff length =l= l. Then tan45°=(10+l)/d=1\tan 45° = (10+l)/d = 1, so 10+l=10310+l = 10\sqrt{3}.

Thus l=10(31)=10(0.732)=7.32l = 10(\sqrt{3}-1) = 10(0.732) = 7.32 m.

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