Find the smallest among the following ? 4√6, √2, 3√4 and √3 Option 1: 4√6 Option 2: √2 Option 3: 3√4 Option 4: √3

Answer: √2. Solution: Convert to decimals: 4√6 1.565, √2 1.414, 3√4 1.587, √3 1.732. Smallest is √2.

Quantitative Reasoning

Number System

Medium

Find the smallest among the following ?

$\sqrt[4]{6}, \sqrt{2}, \sqrt[3]{4}$ and $\sqrt{3}$

$\sqrt[4]{6}$

$\sqrt{2}$

$\sqrt[3]{4}$

$\sqrt{3}$

✅ Correct Option: 2

Convert to decimals: $\sqrt[4]{6} \approx 1.565$ , $\sqrt{2} \approx 1.414$ , $\sqrt[3]{4} \approx 1.587$ , $\sqrt{3} \approx 1.732$ . Smallest is $\sqrt{2}$ .

2022: 6 Aug Shift 1

Ratio $5^{8.14} : 5^{5.14}$ is equal to:

2022: 26 Aug Shift 1

The value of $\left(\frac{8}{125}\right)^{\frac{-4}{3}}$ is __________

2025: 20 May Shift 2

Match List-I with List-II

List-I	List-II
(A) The least number that must be subtracted from 2025 to get a number exactly divisible by 17	(I) 5
(B) The least number that must be added to $1057^{5}$ to get a number exactly divisible by 23	(II) 2
(C) Unit digit of $6^{15}-7^4$	(III) 0
(D) Find the product of any number and the 1st whole number	(IV) 1

Choose the correct answer from the options given below:

2022: 17 Aug Shift 1

The value of $\left(\frac{x}{y}\right)^{2a-3b} \times \left(\frac{x}{y}\right)^{3b-4c} \times \left(\frac{x}{y}\right)^{4c-2a}$

2022: 23 Aug Shift 1

The sum of greatest five digits and lowest/smallest four digits number is:

2025: 3 June Shift 2

Which one of the following is/are correct?

(A) Every irrational number is a real number.

(B) Every real number is an irrational number.

(D) The product or quotient of a non-zero rational number with an irrational number is an irrational number.

Choose the correct answer from the options given below:

Find the smallest among the following ? 64,2,43\sqrt[4]{6}, \sqrt{2}, \sqrt[3]{4}46​,2​,34​ and 3\sqrt{3}3​

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

Find the smallest among the following ?

$\sqrt[4]{6}, \sqrt{2}, \sqrt[3]{4}$ and $\sqrt{3}$