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Two persons A and B start from the same point to travel from Chandigarh to Ambala. The distance between Chandigarh and Ambala is 60 km60 \text{ km}. Speed of A is 4 km/hr4 \text{ km/hr} slower than B. B, when reaches Ambala, starts back via the same route without taking any rest and meets A who was still 12 km12 \text{ km} away from Ambala. Find the speed of A.

Solution

✅ Correct Option: 2

Let speed of A = xx km/hr

Then speed of B = (x+4)(x+4) km/hr

When they meet:

Distance covered by A = 4848 km (as A is 12 km away from Ambala)

Distance covered by B = 60+60−48=7260 + 60 - 48 = 72 km (B went to Ambala and came back until meeting point)

Time taken is same for both:

48x=72x+4\frac{48}{x} = \frac{72}{x+4}

Cross multiply:

48(x+4)=72x48(x+4) = 72x

48x+192=72x48x + 192 = 72x

192=24x192 = 24x

x=8x = 8

Therefore, speed of A = 88 km/hr

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