In a rhombus, the length of the two diagonals are 40m and 30m respectively. Its perimeter will be Option 1: 100 m Option 2: 70 m Option 3: 80 m Option 4: 90 m

Answer: 100 m. Solution: Given: Diagonal 1 (d_1) = 40m Diagonal 2 (d_2) = 30m In a rhombus, using diagonals to find side (s): s^2 = (d_1/2)^2 + (d_2/2)^2 s^2 = (40/2)^2 + (30/2)^2 s^2 = 400 + 225 s^2 = 625 s = 25 meters Perimeter of rhombus = 4s = 4 × 25 = 100 meters Therefore, the perimeter is 100 meters.

Geometry

Quadrilaterals

Easy

In a rhombus, the length of the two diagonals are 40m and 30m respectively. Its perimeter will be

100 m

70 m

80 m

90 m

✅ Correct Option: 1

Given:

Diagonal 1 $(d_1)$ = 40m

Diagonal 2 $(d_2)$ = 30m

In a rhombus, using diagonals to find side $(s)$ :

$s^2 = (\frac{d_1}{2})^2 + (\frac{d_2}{2})^2$

$s^2 = (\frac{40}{2})^2 + (\frac{30}{2})^2$

$s^2 = 400 + 225$

$s^2 = 625$

$s = 25$ meters

Perimeter of rhombus = $4s$

$= 4 × 25$

$= 100$ meters

Therefore, the perimeter is $100$ meters.

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