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A train starts full of passengers. At the first station, it drops one third of passengers and takes 280 more. At the second station, it drops one half of the new total and takes 12 more. On arriving at the third station, it is found to have 248 passengers. The number of passengers in the beginning was

Solution

✅ Correct Option: 2

Let initial passengers = xx

After first station:

2x3+280\frac{2x}{3} + 280 passengers (drops 13\frac{1}{3} and adds 280)

After second station:

12(2x3+280)+12\frac{1}{2}(\frac{2x}{3} + 280) + 12 passengers (drops half and adds 12)

=x3+140+12= \frac{x}{3} + 140 + 12

=x3+152= \frac{x}{3} + 152

After third station = 248 passengers

Therefore:

x3+152=248\frac{x}{3} + 152 = 248

x3=96\frac{x}{3} = 96

x=288x = 288

The initial number of passengers was 288.

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