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If ∣x+1∣+(y+2)2=0|x+1| + (y+2)^2 = 0 and ax−3ay=1ax - 3ay = 1, then the value of aa is

Solution

✅ Correct Option: 1

We know that a mod function will always be non-negative, and a square would also be non-negative. If the sum of both is 0, then both the terms have to equal 0.

Solution figure for IPMAT Indore 2024 MCQ question 3 (Algebra)

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