10:[["$","title","0",{"children":"IPMAT Indore - The number of real solutions of the equation x^2 - 10|x| - 56 = 0 is | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined There are two cases when we open the modulus: I. Positive Sign (assumption: x>0) x^2 - 10|x| - 56 = 0 x^2 - 10x - 56 = 0 x = 14, -4 Note: Become smart in finding the values of x without writing all the steps (you find the two numbers to split the midd<= term, reverse the signs). Since our assumption was x>0, then only x=14 is the accepted value.

II. Negative Sign (assumption: x<0) x^2 - 10|x| - 56 = 0 x^2 + 10x - 56 = 0 x = -14, 4 Since our assumption was x<0, then only x=-14 is the accepted value. Thus, there are only 2 solutions.

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II. Negative Sign (assumption: x<0) x^2 - 10|x| - 56 = 0 x^2 + 10x - 56 = 0 x = -14, 4 Since our assumption was x<0, then only x=-14 is the accepted value. Thus, there are only 2 solutions.

iframe width: 100%; aspect-ratio: 16 / 9; "}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/ipmat-indore/2024/MCQ/4"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Indore Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"IPMAT Indore - The number of real solutions of the equation x^2 - 10|x| - 56 = 0 is | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined There are two cases when we open the modulus: I. Positive Sign (assumption: x>0) x^2 - 10|x| - 56 = 0 x^2 - 10x - 56 = 0 x = 14, -4 Note: Become smart in finding the values of x without writing all the steps (you find the two numbers to split the midd<= term, reverse the signs). Since our assumption was x>0, then only x=14 is the accepted value.

II. Negative Sign (assumption: x<0) x^2 - 10|x| - 56 = 0 x^2 + 10x - 56 = 0 x = -14, 4 Since our assumption was x<0, then only x=-14 is the accepted value. Thus, there are only 2 solutions.

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IPMAT Indore (MCQ) PYQs

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