IPMAT IndoreGeometry > Hard(33+π)k224\left(3\sqrt{3} + \pi\right) \frac{k^2}{24}(33+π)24k2(33+π)k26\left(3\sqrt{3} + \pi\right) \frac{k^2}{6}(33+π)6k2(33−π)k224\left(3\sqrt{3} - \pi\right) \frac{k^2}{24}(33−π)24k2(33+π)k26\left(3\sqrt{3} + \pi\right) \frac{k^2}{6}(33+π)6k2✅ Correct Option: 1Related questions:IPMAT Indore 2025In triangle ABC,AB=AC=x,∠ABC=θABC, AB = AC = x, ∠ABC = \thetaABC,AB=AC=x,∠ABC=θ and the circumradius is equal to yyy. Then xy\frac{x}{y}yx equalsIPMAT Indore 2024The number of triangles with integer sides and with perimeter 15 is:IPMAT Indore 2024The side AB of a triangle ABC is c. The median BD is of length k. If ∠BDA=θ\angle BDA = \theta∠BDA=θ and θ<90∘\theta < 90^\circθ<90∘, then the area of triangle ABC is