IPMAT Indore - Let ABC be an equilateral triangle, with each side of length k. If a circle is drawn with diameter AB, then the area of the portion of the triangle lying inside the circle is | PYQs + Solutions

IPMAT Indore

Geometry

Hard

$\left(3\sqrt{3} + \pi\right) \frac{k^2}{24}$

$\left(3\sqrt{3} + \pi\right) \frac{k^2}{6}$

$\left(3\sqrt{3} - \pi\right) \frac{k^2}{24}$

$\left(3\sqrt{3} + \pi\right) \frac{k^2}{6}$

✅ Correct Option: 1

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