IPMAT IndoreGeometry > Hardk2sinθ2+ksinθc2+k2sin2θ\dfrac{k^2 \sin \theta}{2} + k \sin \theta \sqrt{c^2 + k^2 \sin^2 \theta}2k2sinθ+ksinθc2+k2sin2θk2sin2θ2+ksinθc2−k2sin2θ\dfrac{k^2 \sin 2\theta}{2} + k \sin \theta \sqrt{c^2 - k^2 \sin^2 \theta}2k2sin2θ+ksinθc2−k2sin2θk2cos2θ2+ksinθc2−k2sin2θ\dfrac{k^2 \cos 2\theta}{2} + k \sin \theta \sqrt{c^2 - k^2 \sin^2 \theta}2k2cos2θ+ksinθc2−k2sin2θk2cosθ2+ksinθc2+k2sin2θ\dfrac{k^2 \cos \theta}{2} + k \sin \theta \sqrt{c^2 + k^2 \sin^2 \theta}2k2cosθ+ksinθc2+k2sin2θ✅ Correct Option: 2Related questions:IPMAT Indore 2025In triangle ABC,AB=AC=x,∠ABC=θABC, AB = AC = x, ∠ABC = \thetaABC,AB=AC=x,∠ABC=θ and the circumradius is equal to yyy. Then xy\frac{x}{y}yx equalsIPMAT Indore 2023In a triangle ABC, let D be the midpoint of BC, and AM be the altitude on BC. If the lengths of AB, BC and CA are in the ratio of 2:4:3, then the ratio of the lengths of BM and AD would beIPMAT Indore 2020The number of acute angled triangles whose sides are three consecutive positive integers and whose perimeter is at most 100 is