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IPMAT Indore 2022 PYQsShort Answers (Quants). Free, no login required.

Given that f(x)=∣x∣+2∣x−1∣+∣x−2∣+∣x−4∣+∣x−6∣+2∣x−10∣,x∈(−∞,∞)f(x)=|x|+2|x-1|+|x-2|+|x-4|+|x-6|+2|x-10|, x \in(-\infty, \infty) the minimum value of f(x)f(x) is _________.

Entered answer:

Solution

✅ Correct Answer: 26
Solution figure for IPMAT Indore 2022 SA question 6 (Algebra)

How to find critical point? Equate the stuff within the modulus to 00.

∣x∣→x=0|x| \rightarrow \boxed{x=0}

∣x−1∣→x−1=0→x=1|x-1| \rightarrow x-1=0 \rightarrow \boxed{x =1}

How to find the median of critical points? Note: Repeat the critical point by the number of times the term appears.

In our question, the points are: 0,1,1,2,4,6,10,100, 1, 1, 2, 4, 6, 10, 10. Hence, median =2,4= 2, 4.

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