IPMAT Indore 2019Geometry > Hard15+352\frac{\sqrt{15} + \sqrt{35}}{2}215+35 m888 m13\sqrt{13}13 m666 m✅ Correct Option: 1Related questions:A circle touches the y-axis at (0,4)(0, 4)(0,4) and passes through the point (−2,0)(-2, 0)(−2,0). Then the radius of the circle isThe equation x2+y2−2x−4y+5=0x^2 + y^2 - 2x - 4y +5 = 0x2+y2−2x−4y+5=0 representsA circle of radius 131313 cm touches the adjacent sides AB and BC of a square ABCD at M and N, respectively. If AB = 181818 cm and the circle intersects the other two sides CD and DA at P and Q, respectively, then the area, in sq. cm, of triangle PMD is