IPMAT Indore 2019Algebra > Medium(12,1)\left( \frac{1}{2}, 1 \right)(21,1)(12,∞)\left( \frac{1}{2}, \infty \right)(21,∞)(−∞,12)\left( -\infty, \frac{1}{2} \right)(−∞,21)(−∞,12)∪(1,∞)\left( -\infty, \frac{1}{2} \right) \cup \left( 1, \infty \right)(−∞,21)∪(1,∞)✅ Correct Option: 4Related questions:IPMAT Indore 2019If x∈(a,b)x ∈ (a, b)x∈(a,b) satisfies the inequality x−3x2+3x+2≥1\dfrac{x - 3}{x^2 + 3x + 2} \geq 1x2+3x+2x−3≥1, then the largest possible value of b−ab - ab−a isIPMAT Indore 2019The set of all real values of x satisfying the inequality x2(x+1)(x−1)(2x+1)3>0\dfrac{x^2(x+1)}{(x-1)(2x+1)^3} > 0(x−1)(2x+1)3x2(x+1)>0 isIPMAT Indore 2019The smallest possible number of students in a class if the girls in the class are less than 50% but more than 48% is