CUET Mathematics: AlgebraMatrices & Determinants. Free, no login required.

Q1:

2023: 22 May Shift 3

Matrices & Determinants

Medium

Core

If A=(cos⁡2θsin⁡2θ−sin⁡2θcos⁡2θ)A = \begin{pmatrix} \cos 2\theta & \sin 2\theta \\ -\sin 2\theta & \cos 2\theta \end{pmatrix}, then A2=A^2 =

Answer options
Option 1
Correct Answer
Explanation for 2023: 22 May Shift 3 MAT question 1

Q2:

2023: 22 May Shift 3

Matrices & Determinants

Medium

Core

Which of the following statements are correct ?

(A) ∣A′∣=∣A∣|A'| = |A|, where A is the transpose of matrix A

(B) If A=[aij]3×3A = [a_{ij}]_{3 \times 3}, then ∣4A∣=64∣A∣|4A| = 64|A|

(C) ∣A∣=∣adj A∣n−1|A| = |\text{adj } A|^{n-1}, where n is the order of the matrix

(D) If A is an invertible matrix of order 2, then det⁡(A−1)\det(A^{-1}) is equal to 1det⁡(A)\frac{1}{\det(A)}

Choose the correct answer from the options given below :

Answer options
Option 1
Correct Answer
Explanation for 2023: 22 May Shift 3 MAT question 2

Q3:

2023: 30 May Shift 3

Matrices & Determinants

Easy

Common

If ∣3x47x∣=∣6321∣\begin{vmatrix} 3x & 4 \\ 7 & x \end{vmatrix} = \begin{vmatrix} 6 & 3 \\ 2 & 1 \end{vmatrix} then :

Answer options
Option 4
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 3

Q4:

2023: 30 May Shift 3

Matrices & Determinants

Easy

Common

Given A=[2314]A = \begin{bmatrix} 2 & 3 \\ 1 & 4 \end{bmatrix} and B=[xy14]B = \begin{bmatrix} x & y \\ 1 & 4 \end{bmatrix}, If A=BA = B, then xx and yy are :

Answer options
Option 1
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 4

Q5:

2023: 30 May Shift 3

Matrices & Determinants

Easy

Common

The sum of the products of elements of any row with the cofactors of corresponding elements is equal to :

Answer options
Option 1
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 5

Q6:

2023: 30 May Shift 3

Matrices & Determinants

Easy

Common

If order of matrix A is m×pm \times p and order of matrix B is p×np \times n, then what is the order of matrix AB ?

Answer options
Option 2
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 6

Q7:

2023: 30 May Shift 3

Matrices & Determinants

Easy

Core

If matrix A=[3xy0]A = \begin{bmatrix} 3 & x \\ y & 0 \end{bmatrix} and A′=AA' = A, then :

Answer options
Option 1
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 7

Q8:

2023: 30 May Shift 3

Matrices & Determinants

Medium

Core

If A and B are invertible matrices of order 3, ∣A∣=2|A| = 2 and ∣(AB)−1∣=−16|(AB)^{-1}| = -\frac{1}{6}, then the value of ∣B∣|B| is :

Answer options
Option 2
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 8

Q9:

2023: 30 May Shift 3

Matrices & Determinants

Medium

Core

Let A=[1−23121λ2−3]A = \begin{bmatrix} 1 & -2 & 3 \\ 1 & 2 & 1 \\ \lambda & 2 & -3 \end{bmatrix}. If A−1A^{-1} does not exist, then λ=\lambda =

Answer options
Option 4
Correct Answer
Explanation for 2023: 30 May Shift 3 MAT question 9

Q10:

2023: 30 May Shift 3

Matrices & Determinants

Hard

Core

If a, b and c are all different from zero and ∣1+a1111+b1111+c∣=0\begin{vmatrix} 1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c \end{vmatrix} = 0, then the value of 1a+1b+1c\frac{1}{a} + \frac{1}{b} + \frac{1}{c} is :

Answer options

Q11:

2023: 30 May Shift 3

Matrices & Determinants

Medium

Core

If A=[1−23−424]A = \begin{bmatrix} 1 & -2 & 3 \\ -4 & 2 & 4 \end{bmatrix} and B=[1−23−424]B = \begin{bmatrix} 1 & -2 \\ 3 & -4 \\ 2 & 4 \end{bmatrix} then product AB is :

Answer options

Q12:

2023: 30 May Shift 3

Matrices & Determinants

Medium

Core

If A=[31−12]A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}, then A2−5A+7I=A^2 - 5A + 7I =

Answer options

Q13:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Common

Let A=[aij]A = [a_{ij}] be a 2×22 \times 2 matrix such that aij=∣−3i+j∣2a_{ij} = \frac{|-3i+j|}{2} then a21a_{21} is :

Answer options

Q14:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Common

If A=[−26−5−1]A = \begin{bmatrix} -2 & 6 \\ -5 & -1 \end{bmatrix} then A−1A^{-1} is :

Answer options

Q15:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Common

The value of ∣3/21/23/21/2∣\begin{vmatrix} \sqrt{3}/2 & 1/2 \\ \sqrt{3}/2 & 1/2 \end{vmatrix}

Answer options

Q16:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Common

If A is a square matrix of order 3 such that ∣A∣=2|A|=2, then the value of ∣adj(adjA)∣|adj(adj A)| is :

Answer options

Q17:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Core

The value of 2y−3x2y - 3x, if 2[x57y−3]+[3−412]=[761514]2\begin{bmatrix} x & 5 \\ 7 & y-3 \end{bmatrix} + \begin{bmatrix} 3 & -4 \\ 1 & 2 \end{bmatrix} = \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix} is :

Answer options

Q18:

2023: 15 June Shift 2

Matrices & Determinants

Hard

Core

Match List - I with List - II. If A=∣3−2321−14−32∣A = \begin{vmatrix} 3 & -2 & 3 \\ 2 & 1 & -1 \\ 4 & -3 & 2 \end{vmatrix}

List - IList - II
(A) M23M_{23}(I) −17-17
(B) A32+a13A_{32} + a_{13}(II) −1-1
(C) A(III) 0
(D) a13A12+a23A22+a33A32a_{13}A_{12} + a_{23}A_{22} + a_{33}A_{32}(IV) 12

Choose the correct answer from the options given below :

Answer options

Q19:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Core

The number of square matrices of order 2 using numbers 1 and −1-1 exactly once and the number 0 twice is :

Answer options

Q20:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Core

Let ∣3x−714∣=∣324x∣\begin{vmatrix} 3x & -7 \\ 1 & 4 \end{vmatrix} = \begin{vmatrix} 3 & 2 \\ 4 & x \end{vmatrix}, then value of xx is :

Answer options

Q21:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Core

The value of the determinant ∣acos⁡θbsin⁡θ0−bsin⁡θacos⁡θ000c∣\begin{vmatrix} a\cos\theta & b\sin\theta & 0 \\ -b\sin\theta & a\cos\theta & 0 \\ 0 & 0 & c \end{vmatrix} is :

Answer options

Q22:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Core

If the points (2, 1), (−1,4)(-1, 4) and (a, 3) are collinear then the value/(s) of a is/(are) :

Answer options

Q23:

2023: 15 June Shift 2

Matrices & Determinants

Easy

Applied

If [32x+5y−2x+4y7−5]=[310−227−5]\begin{bmatrix} 3 & 2x+5y & -2 \\ x+4y & 7 & -5 \end{bmatrix} = \begin{bmatrix} 3 & 10 & -2 \\ 2 & 7 & -5 \end{bmatrix} Then the values of xx and yy are :

Answer options

Q24:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Applied

If A is a square matrix of order 3 and ∣A∣=5|A| = 5, then ∣adj(adjA)∣|adj(adjA)| is :

Answer options

Q25:

2023: 15 June Shift 2

Matrices & Determinants

Medium

Applied

If the matrix A=[x−2−5y20−9103z0]A = \begin{bmatrix} x & -2 & -5y \\ 2 & 0 & -9 \\ 10 & 3z & 0 \end{bmatrix} is skew-symmetric, then the value of (2x−3y+4z)(2x - 3y + 4z) is :

Answer options

Q26:

2022: 7 Aug Shift 2

Matrices & Determinants

Easy

Core

If A is a square matrix of order 3 and ∣A∣|A| is 2, then value of ∣adj(A)∣|adj(A)| is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 26

Q27:

2022: 7 Aug Shift 2

Matrices & Determinants

Easy

Core

Let A and B be square matrices of order 3 and k is a constant. If ∣A∣≠0|A| \neq 0 and ∣B∣≠0|B| \neq 0, where ∣A∣|A| represents the determinant of A, then which of the following statements are true ? (where A' denotes the transpose of matrix A)

(A) (AB)−1=B−1A−1(AB)^{-1} = B^{-1} A^{-1}

(B) (A+B)′=A′×B′(A+B)' = A' \times B'

(C) (AB)′=A′B′(AB)' = A'B'

(D) ∣kA∣=k3∣A∣|kA| = k^3 |A|

(E) ∣A′∣=∣A∣|A'| = |A|

Choose the correct answer from the options given below :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 27

Q28:

2022: 7 Aug Shift 2

Matrices & Determinants

Medium

Core

The number of all possible non-singular matrices of order 2×22 \times 2 with each entry 0 or 1 is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 28

Q29:

2022: 7 Aug Shift 2

Matrices & Determinants

Easy

Core

Let A=(aij)A = (a_{ij}) and B=(bij)B = (b_{ij}) are square matrices of same order.

(A) The number of possible matrices of order 2×22 \times 2 with entries −1,0,1-1, 0, 1 is 81.

(B) A+A′A + A' is skew symmetric matrix

(C) A⋅A−1=0A \cdot A^{-1} = 0, ∣A∣≠0|A| \neq 0

(D) A is skew symmetric matrix if aij=−ajia_{ij} = -a_{ji} for all i,ji, j

(E) (AB)′=A′B′(AB)' = A'B'

Choose the correct answer from the options given below :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 29

Q30:

2022: 7 Aug Shift 2

Matrices & Determinants

Medium

Core

Match List - I with List - II.

List - IList - II
(A)A=[6923]A = \begin{bmatrix} 6 & 9 \\ 2 & 3 \end{bmatrix}, B=[260798]B = \begin{bmatrix} 2 & 6 & 0 \\ 7 & 9 & 8 \end{bmatrix}, AB will be(I)[7511772353924]\begin{bmatrix} 75 & 117 & 72 \\ 35 & 39 & 24 \end{bmatrix}
(B)P=[8453017195]P = \begin{bmatrix} 8 & 45 & 30 \\ 17 & 19 & 5 \end{bmatrix}, Q=[67724283019]Q = \begin{bmatrix} 67 & 72 & 42 \\ 8 & 30 & 19 \end{bmatrix}, P+Q will be(II)[7511772253924]\begin{bmatrix} 75 & 117 & 72 \\ 25 & 39 & 24 \end{bmatrix}
(C)[854269734250]−[10−75−338326]\begin{bmatrix} 85 & 42 & 69 \\ 73 & 42 & 50 \end{bmatrix} - \begin{bmatrix} 10 & -75 & -3 \\ 38 & 3 & 26 \end{bmatrix}(III)[7511772254924]\begin{bmatrix} 75 & 117 & 72 \\ 25 & 49 & 24 \end{bmatrix}
(D)2[343630121820]+[75512113−16]2 \begin{bmatrix} 34 & 36 & 30 \\ 12 & 18 & 20 \end{bmatrix} + \begin{bmatrix} 7 & 55 & 12 \\ 1 & 13 & -16 \end{bmatrix}(IV)[7512772254924]\begin{bmatrix} 75 & 127 & 72 \\ 25 & 49 & 24 \end{bmatrix}

Choose the correct answer from the options given below :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 30