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Two boys A and B start at the same time to ride from Delhi to Meerut, 60 km away. A travels 4 km an hour slower than B. B reaches Meerut and at once turns back and meets A at 12 km from Meerut. Find A's speed

Solution

✅ Correct Option: 1

When they meet, A has covered 60−12=4860 - 12 = 48 km and B has covered 60+12=7260 + 12 = 72 km in the same time. If A's speed is aa, then 48a=72a+4\frac{48}{a} = \frac{72}{a+4}, so 48a+192=72a48a + 192 = 72a, giving 24a=19224a = 192 and a=8a = 8 km/hr.

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