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Solution

✅ Correct Option: 1

Note that 72=49=48+17^2 = 49 = 48 + 1, so 72≡1(mod48)7^2 \equiv 1 \pmod{48}. Since 126126 is even, 7126=(72)63≡163=1(mod48)7^{126} = (7^2)^{63} \equiv 1^{63} = 1 \pmod{48}. The remainder is 1.

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