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The angle of elevation of the sun, when the length of the shadow of a tower is 1/√3 times the height of the tower, is

Solution

✅ Correct Option: 3

Let the height of the tower be hh.

The shadow length is 13×h=h3\frac{1}{\sqrt{3}} \times h = \frac{h}{\sqrt{3}}.

The tower, its shadow, and the line from the sun form a right-angled triangle where:

  • Height of tower (perpendicular) = hh
  • Shadow length (base) = h3\frac{h}{\sqrt{3}}
  • Angle of elevation = θ\theta

Using the tangent ratio:

tan⁡θ=HeightShadow\tan \theta = \frac{\text{Height}}{\text{Shadow}}

tan⁡θ=hh3\tan \theta = \frac{h}{\frac{h}{\sqrt{3}}}

tan⁡θ=h×3h\tan \theta = h \times \frac{\sqrt{3}}{h}

tan⁡θ=3\tan \theta = \sqrt{3}


From standard trigonometric values, tan⁡60°=3\tan 60° = \sqrt{3}.

Therefore, θ=60°\theta = 60°.

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