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A can do a certain work in 12 days. B is 60% more efficient than A. How many days does B alone take to do the same work?

Solution

✅ Correct Option: 2

Efficiency and time are inversely proportional. If A's efficiency is 100100, B's is 160160, so the ratio of efficiencies is 5:85 : 8 and the ratio of times taken is 8:58 : 5.

B's time =12×58=152= 12 \times \frac{5}{8} = \frac{15}{2} days.

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