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Consider the surface areas of the following solids:

(A) A cuboid of 10 cm long, 7 cm broad, and 5 cm high.

(B) A cylinder of radius 3.5 cm and height 60 cm.

(C) A cone of radius 6 cm and height 8 cm.

(D) A sphere of radius 12 cm.

Arrange the above in decreasing order.

Solution

✅ Correct Option: 4

Cuboid: 2(10⋅7+7⋅5+5⋅10)=3102(10 \cdot 7 + 7 \cdot 5 + 5 \cdot 10) = 310.

Cylinder: 2πr(r+h)=2⋅227⋅3.5⋅63.5=13972\pi r(r+h) = 2 \cdot \frac{22}{7} \cdot 3.5 \cdot 63.5 = 1397.

Cone: slant l=10l = 10, so πr(l+r)=96π≈301.7\pi r(l+r) = 96\pi \approx 301.7.

Sphere: 4πr2=576π≈1809.64\pi r^2 = 576\pi \approx 1809.6.

Decreasing order: (D), (B), (A), (C).

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