Geometry

Trigonometry

Easy

A tower is 20 m high. The angle of elevation of the top of the tower from a point on the ground is 30°. Find the distance of the point from the base of the tower.

50√3 m

20√3 m

10√3 m

30√3 m

✅ Correct Option: 2

Let the distance from the base be $d$ . In the right triangle formed, $\tan 30^\circ = \frac{20}{d}$ .

Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$ , we get $\frac{1}{\sqrt{3}} = \frac{20}{d}$ , so $d = 20\sqrt{3}$ m.

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A tower is 20 m high. The angle of elevation of the top of the tower from a point on the ground is 30°. Find the distance of the point from the base of the tower.

Solution

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