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A man 2 m tall is walking away from a street light of height 10 m. If the length of his shadow is 6 m, find the distance of the man from the street light.

Solution

✅ Correct Option: 2

Let the man be dd m from the pole. The triangles formed by the pole and by the man are similar.

210=6d+6⇒2(d+6)=60⇒d+6=30⇒d=24\frac{2}{10} = \frac{6}{d+6} \Rightarrow 2(d+6) = 60 \Rightarrow d + 6 = 30 \Rightarrow d = 24 m.

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