A wire is looped in the form of a circle of diameter 70 cm. It is bent again into a square form. What will be the approximate length of the diagonal of the largest possible square? (Assume $\pi = 22/7$)

The wire is shaped as a circle with diameter 70 cm. When reshaped into a square, the wire length remains constant.

The circumference of the circle equals the length of the wire:

Circumference $= \pi \times \text{diameter}$

$= \frac{22}{7} \times 70$

$= 22 \times 10$

$= 220$ cm

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When the wire is bent into a square, the perimeter of the square equals the wire length.

Perimeter of square $= 4 \times \text{side}$

$220 = 4 \times \text{side}$

$\text{side} = \frac{220}{4}$

$\text{side} = 55$ cm

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The diagonal of a square with side length $s$ is given by:

Diagonal $= s\sqrt{2}$

Diagonal $= 55\sqrt{2}$ cm

Therefore, the length of the diagonal is $55\sqrt{2}$ cm.