In parallelogram ABCD, angle A is greater than angle B by 10, then measure of angle D is Option 1: 95 Option 2: 75 Option 3: 85 Option 4: 65

Answer: 85. Solution: In a parallelogram, adjacent angles are supplementary: A + B = 180. Given A = B + 10, so ( B + 10) + B = 180, giving B = 85. Since D = B (opposite angles), D = 85.

Geometry

Quadrilaterals

Medium

In parallelogram ABCD, angle A is greater than angle B by 10 $\degree$ , then measure of angle D is

95 $\degree$

75 $\degree$

85 $\degree$

65 $\degree$

✅ Correct Option: 3

In a parallelogram, adjacent angles are supplementary: $\angle A + \angle B = 180\degree$ . Given $\angle A = \angle B + 10$ , so $(\angle B + 10) + \angle B = 180$ , giving $\angle B = 85\degree$ . Since $\angle D = \angle B$ (opposite angles), $\angle D = 85\degree$ .

2022: 6 Oct Shift 1

The area of Trapezum DGCE is.

2025: 30 May Shift 2

If the points A(3, 0), B(x, 5), C(-1, 4) and D(-2, -1) are the vertices of a rhombus, taken in order, find the value of x.

2022: 17 Aug Shift 1

The side of the square is

2022: 24 Aug Shift 1

Side of the rhombus is :

2026: 29 May Shift 1

Find the maximum distance between two points on the perimeter of a rectangular garden whose length and breadth are 20 meter and 15 meter.

2024

In a square, lengths of the diagonals are $(4k + 6)$ cm and $(7k − 3)$ cm. The area of the square (in cm²) is:

In parallelogram ABCD, angle A is greater than angle B by 10°\degree°, then measure of angle D is

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)

In parallelogram ABCD, angle A is greater than angle B by 10 $\degree$ , then measure of angle D is