Skip to main contentSkip to solution

Two trains of equal length are running from the same origin on parallel tracks in the same direction, at the speeds of 58 km/hr and 73 km/hr, respectively. The faster train passes the other train in 144 seconds. What is the length (in meters) of each train?

Solution

✅ Correct Option: 3

Two trains of equal length are running in the same direction on parallel tracks. The slower train travels at 58 km/hr and the faster train travels at 73 km/hr.

Since both trains move in the same direction, the relative speed determines how fast the faster train gains on the slower train.

Relative Speed =73−58=15= 73 - 58 = 15 km/hr


The time is given in seconds and the answer is needed in meters, so the speed must be converted to m/s.

To convert km/hr to m/s, multiply by 518\frac{5}{18}:

15×51815 \times \frac{5}{18}

=7518= \frac{75}{18}

=256= \frac{25}{6} m/s


When the faster train completely passes the slower train, it must cover the length of both trains. Since both trains have equal length LL:

Total distance covered =L+L=2L= L + L = 2L


Using the relationship between distance, speed, and time:

2L=256×1442L = \frac{25}{6} \times 144

2L=25×14462L = \frac{25 \times 144}{6}

2L=360062L = \frac{3600}{6}

2L=6002L = 600

L=300L = 300 meters

Therefore, each train is 300 meters long.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question