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If a:b=125:310a:b = \frac{12}{5}:\frac{3}{10} and b:c=79:127b:c = \frac{7}{9}:\frac{12}{7} then a:ca:c is

Solution

✅ Correct Option: 1

The given ratios are a:b=125:310a:b = \frac{12}{5}:\frac{3}{10} and b:c=79:127b:c = \frac{7}{9}:\frac{12}{7}.

To simplify a:b=125:310a:b = \frac{12}{5}:\frac{3}{10}:

ab=12/53/10\frac{a}{b} = \frac{12/5}{3/10}

ab=125×103\frac{a}{b} = \frac{12}{5} \times \frac{10}{3}

ab=12015\frac{a}{b} = \frac{120}{15}

ab=8\frac{a}{b} = 8


To simplify b:c=79:127b:c = \frac{7}{9}:\frac{12}{7}:

bc=7/912/7\frac{b}{c} = \frac{7/9}{12/7}

bc=79×712\frac{b}{c} = \frac{7}{9} \times \frac{7}{12}

bc=49108\frac{b}{c} = \frac{49}{108}


To find a:ca:c:

ac=ab×bc\frac{a}{c} = \frac{a}{b} \times \frac{b}{c}

ac=8×49108\frac{a}{c} = 8 \times \frac{49}{108}

ac=392108\frac{a}{c} = \frac{392}{108}

ac=9827\frac{a}{c} = \frac{98}{27}

Therefore, a:c=9827a:c = \dfrac{98}{27}

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