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In how many years will a sum of money double itself at 12.5% p.a., at simple interest?

Solution

✅ Correct Option: 4

For money to double, the amount becomes 2 times the principal.

If the principal is PP, the final amount is 2P2P.

The simple interest earned is:

SI=2P−PSI = 2P - P

SI=PSI = P


The simple interest formula is:

SI=P×R×T100SI = \dfrac{P \times R \times T}{100}

Where PP is the principal, R=12.5%R = 12.5\% per annum, and TT is the time in years.


Since the simple interest equals the principal:

P=P×12.5×T100P = \dfrac{P \times 12.5 \times T}{100}

Dividing both sides by PP:

1=12.5×T1001 = \dfrac{12.5 \times T}{100}

100=12.5×T100 = 12.5 \times T

T=10012.5T = \dfrac{100}{12.5}

T=100252T = \dfrac{100}{\frac{25}{2}}

T=100×225T = 100 \times \dfrac{2}{25}

T=20025T = \dfrac{200}{25}

T=8T = 8


Therefore, the sum of money will double itself in 8 years.

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