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When a particular wire is bent into the shape of a square, then the area of the square turns out to be 81cm281cm^2. When the same wire is bent into a circle, then the radius of the circle (correct to two decimal places) is

Solution

Correct Option: 2

The wire is bent into a square with area 81 cm281 \text{ cm}^2.

Area of square =(side)2= (\text{side})^2

(side)2=81(\text{side})^2 = 81

side=81=9 cm\text{side} = \sqrt{81} = 9 \text{ cm}


The perimeter of the square equals the length of the wire.

Perimeter of square =4×side= 4 \times \text{side}

Length of wire =4×9=36 cm= 4 \times 9 = 36 \text{ cm}


When the same wire is bent into a circle, the length of the wire equals the circumference of the circle.

Circumference =2πr= 2\pi r

2πr=362\pi r = 36

r=362πr = \dfrac{36}{2\pi}

r=18πr = \dfrac{18}{\pi}


r=18πr = \dfrac{18}{\pi}

r=183.14159r = \dfrac{18}{3.14159}

r=5.729...r = 5.729...

r5.73 cmr \approx 5.73 \text{ cm}

Therefore, the radius of the circle is 5.73 cm5.73 \text{ cm}.

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