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Linear equations 3x+5y=193x + 5y = 19 and 10x3y=2410x - 3y = 24 have solution x=α3x = \frac{\alpha}{3} and y=β2y = \frac{\beta}{2}, then the value of α+β\alpha + \beta is:

Solution

Correct Option: 2

Substituting x=α3x = \frac{\alpha}{3}, y=β2y = \frac{\beta}{2}: from the first equation, 2α+5β=382\alpha + 5\beta = 38; from the second, 20α9β=14420\alpha - 9\beta = 144. Solving simultaneously gives α=9\alpha = 9, β=4\beta = 4.

So α+β=13\alpha + \beta = 13.

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