IPMAT Indore 2024Geometry > Easy15(5+1)15(\sqrt{5} + 1)15(5+1)20(3+1)20(\sqrt{3} + 1)20(3+1)30303010(3+1)10(\sqrt{3} + 1)10(3+1)✅ Correct Option: 4Related questions:If the angles A,B,CA, B, CA,B,C of a triangle are in arithmetic progression such that sin(2A+B)=1/2\sin(2A + B) = 1/2sin(2A+B)=1/2 then sin(B+2C)\sin(B + 2C)sin(B+2C) is equal toIf sinθ+cosθ=msin \theta + cos \theta = msinθ+cosθ=m, then sin6θ+cos6θsin^6 \theta + cos^6 \thetasin6θ+cos6θ equalsThe value of cos2(π8)+cos2(3π8)+cos2(5π8)+cos2(7π8)\cos^2\left(\frac{\pi}{8}\right) + \cos^2\left(\frac{3\pi}{8}\right) + \cos^2\left(\frac{5\pi}{8}\right) + \cos^2\left(\frac{7\pi}{8}\right)cos2(8π)+cos2(83π)+cos2(85π)+cos2(87π) is