Skip to main contentSkip to solution

Let △ABC\triangle ABC be a triangle with AB=ACAB = AC and DD be a point on BCBC such that ∠BAD=30∘\angle BAD = 30^\circ. If EE is a point on ACAC such that AD=AEAD = AE, then ∠CDE\angle CDE equals

Solution

✅ Correct Option: 4
Solution figure for IPMAT Indore 2024 MCQ question 11 (Geometry)

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question