IPMAT IndoreGeometry > Hardk2sinθ2+ksinθc2+k2sin2θ\dfrac{k^2 \sin \theta}{2} + k \sin \theta \sqrt{c^2 + k^2 \sin^2 \theta}2k2sinθ+ksinθc2+k2sin2θk2sin2θ2+ksinθc2−k2sin2θ\dfrac{k^2 \sin 2\theta}{2} + k \sin \theta \sqrt{c^2 - k^2 \sin^2 \theta}2k2sin2θ+ksinθc2−k2sin2θk2cos2θ2+ksinθc2−k2sin2θ\dfrac{k^2 \cos 2\theta}{2} + k \sin \theta \sqrt{c^2 - k^2 \sin^2 \theta}2k2cos2θ+ksinθc2−k2sin2θk2cosθ2+ksinθc2+k2sin2θ\dfrac{k^2 \cos \theta}{2} + k \sin \theta \sqrt{c^2 + k^2 \sin^2 \theta}2k2cosθ+ksinθc2+k2sin2θ✅ Correct Option: 2Related questions:IPMAT Indore 2023In a triangle ABC, let D be the midpoint of BC, and AM be the altitude on BC. If the lengths of AB, BC and CA are in the ratio of 2:4:3, then the ratio of the lengths of BM and AD would beIPMAT Indore 2022In a right-angled triangle ABC, the hypotenuse AC is of length 13 cm. A line drawn connecting the midpoints D and E of sides AB and AC is found to be 6 cm in length. The length of BC isIPMAT Indore 2019The number of points, having both coordinates as integers, that lie in the interior of the triangle with vertices (0,0),(0,31),(0, 0), (0, 31),(0,0),(0,31), and (31,0)(31, 0)(31,0) is