IPMAT Indore 2019Algebra > Medium23002^{300}230032003^{200}32002100+31002^{100} + 3^{100}2100+310041004^{100}4100✅ Correct Option: 2Watch NowGreater Number #1Watch NowGreater Number #2Watch NowSolved ExampleRelated questions:The set of all possible values of f(x)f(x)f(x) for which (81)x+(81)f(x)=3(81)^{x}+(81)^{f(x)}=3(81)x+(81)f(x)=3 isThe greatest number among 23002^{300}2300, 32003^{200}3200, 41004^{100}4100, 2100+31002^{100} + 3^{100}2100+3100 is