ajthebodybuilder
•22d
PW jee long lectures for modern maths
many seniors recommend to solve easy or medium level of jee pyq of chapters relevant in ipmat , instead of seggregating and finding questions myself , can i just finish arjuna jee 24 hr lectures[not passively] + ims module of for eg sequence series to compensate for the jee questions, and skip the jee adv questions and also topics not tested much in ipmat like sigma q's in sequence series [ i have access to jee batch because of my sister]
1 likes•4 comments
Why are we taking NB as 3x? If the distance from N towards A is one quarter of the distance to B , shouldn't NB be 4x?
In this question, even the times at which the shuttle arrives are being counted. Like if we start from 12, then we are also considering that if the person arrives at 12:20 which is also the time at which the local shuttle arrives as a part of the outcomes in which the person will have to wait for more than 6 minutes. But they arrive at the same time so why are we considering that the person will wait till 12:35 when the local shuttle too arrives at 12:20?
By solving this we get one root as 4 and another as 2^-1/3, which is irrational. So both option 1 and 3 are correct then.
In this question, as it was specifically 9, after accounting for atleast one in each of the 4 dice we get a+b+c+d=5 and here each of a,b,c,d can be max 5 meaning each dice can be max 6 so that is valid. But how to solve such a sum if instead of 9, it was asked for something bigger like 12?
In this set, it was stated that at least one car of each variant belonging to each of the three brands was sold. Then in the solution- b cannot be 15 or 5 right because if it is than the diesel jacks and diesel vault would become 0. Then b can only take 9 values....
How does this work for minimum value of intersection
Is diagram the only way to approach? Or is there any ither way to solve it?
The solution is saying to pick 4 containers out of 5 and having 2 choices in each container. But isn't there only 1 container in which all 10 codes are present? I unable to understand the approach given in the solution. Please explain