Match the **LIST-I** with **LIST-II** | | LIST-I (Series) | | LIST-II (Missing term) | |---|---|---|---| | A. | 5, 6, 9, 15, ?, 40 | I. | 31 | | B. | 1, 2, 3, 6, 9, 18, ?, 54 | II. | 39 | | C. | 2, 3, 3, 5, 10, 13, ?, 43, 172, 177 | III. | 25 | | D. | 3, 7, 15, ?, 63, 127 | IV. | 27 |
Solution
✅ Correct Option: 3
A has differences $+1,+3,+6,+10,+15$, so the blank is $15+10=25$ → III. B alternates doubling with adding the previous smaller term: $1,2,3,6,9,18,27,54$ → IV. C follows $+1,\times1,+2,\times2,+3,\times3,+4,\times4,+5$, so $13\times3=39$ → II. D follows $\times2+1$, so the blank is $15\times2+1=31$ → I. Thus A-III, B-IV, C-II, D-I.
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