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Match the LIST-I with LIST-II

LIST-I
(Series)
LIST-II
(Missing term)
A.5, 6, 9, 15, ?, 40I.31
B.1, 2, 3, 6, 9, 18, ?, 54II.39
C.2, 3, 3, 5, 10, 13, ?, 43, 172, 177III.25
D.3, 7, 15, ?, 63, 127IV.27

Solution

✅ Correct Option: 3

A has differences +1,+3,+6,+10,+15+1,+3,+6,+10,+15, so the blank is 15+10=2515+10=25 → III.

B alternates doubling with adding the previous smaller term: 1,2,3,6,9,18,27,541,2,3,6,9,18,27,54 → IV.

C follows +1,×1,+2,×2,+3,×3,+4,×4,+5+1,\times1,+2,\times2,+3,\times3,+4,\times4,+5, so 13×3=3913\times3=39 → II.

D follows ×2+1\times2+1, so the blank is 15×2+1=3115\times2+1=31 → I.

Thus A-III, B-IV, C-II, D-I.

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