The average number of students who qualified in the examination from Kolkata and Delhi is what percent of the average number of students who appeared for the exam from the same cities? (rounded off to 2 digits after decimal)

The question asks us to find the average number of students who qualified from Kolkata and Delhi, and then express it as a percentage of the average number of students who appeared from the same cities.

"A is what percent of B" always means: $\dfrac{A}{B} \times 100$

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Average number of students who qualified from Kolkata and Delhi:

$\dfrac{2250 + 2000}{2} = \dfrac{4250}{2} = 2125$

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Average number of students who appeared from Kolkata and Delhi:

$\dfrac{3250 + 2500}{2} = \dfrac{5750}{2} = 2875$

Average $= \dfrac{\text{Sum of values}}{\text{Number of values}}$, and since there are $2$ cities, we divide by $2$.

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Required percentage:

$\dfrac{2125}{2875} \times 100 = 0.7391304... \times 100 = 73.9130...$

Rounding off to $2$ decimal places — the third decimal digit is $3$, which is less than $5$, so we round down.

$= 73.91\%$

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$\therefore$ Option C is the correct answer.