IPMAT Indore 2024Algebra > MediumEntered answer:✅ Correct Answer: 6Related questions:IPMAT Indore 2019The function f(x)=x3−5x2−8x3f(x) = \dfrac{x^3 - 5x^2 - 8x}{3}f(x)=3x3−5x2−8x isIPMAT Indore 2021Suppose that a real-valued function f(x)f(x)f(x) of real numbers satisfies f(x+xy)=f(x)+f(xyf(x + xy) = f(x) + f(xyf(x+xy)=f(x)+f(xy) for all real x,y,x, y,x,y, and that f(2020)=1f(2020) = 1f(2020)=1. Compute f(2021)f(2021)f(2021).IPMAT Indore 2021If a function f(a)=max(a,0)f(a) = max (a, 0)f(a)=max(a,0) then the smallest integer value of xxx for which the equation f(x−3)+2f(x+1)=8f(x - 3) + 2f(x + 1) = 8f(x−3)+2f(x+1)=8 holds true is _______.