IPMAT Indore - Suppose that a real-valued function f(x) of real numbers satisfies f(x + xy) = f(x) + f(xy) for all real x, y, and that f(2020) = 1. Compute f(2021). | PYQs + Solutions

IPMAT Indore

Algebra

Medium

$\frac{2021}{2020}$

$\frac{2020}{2019}$

$\frac{2020}{2021}$

✅ Correct Option: 1

Watch Now

f(x) = nx

Watch Now

Solved Example

Related questions:

IPMAT Indore 2022

If $f\left(x^{2}+f(y)\right)=x f(x)+y$ for all non-negative integers $x$ and $y$ , then the value of $[f(0)]^{2}+f(0)$ equals _________.

IPMAT Indore 2021

If a function $f(a) = max (a, 0)$ then the smallest integer value of $x$ for which the equation $f(x - 3) + 2f(x + 1) = 8$ holds true is _______.

IPMAT Indore 2022

A set of all possible values the function $f(x)=\dfrac{x}{|x|}$ , where $x \neq 0$ , takes is

IPMAT Indore (MCQ) PYQs